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  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    所以B)=ED,∠AD=∠AB)=2∠C因为∠AED=∠C+∠EDC,所以∠EDC=∠C.所以ED=EC.所以BD=EC所以AC=AE+C=AB+BI).(2)BE=DC+EC.在EB上戟取EF,使得EF=DC,连接AF因为EA=ED,所以/EAD=/E)A,所以2∠DAE+∠AED=180%因为上1)A5+∠B=90,所以2∠DAE+2/B=180°所以∠AED=2∠B=∠CG因为∠B)=∠AB+∠AE)=∠CID+∠C.所以∠AEB=∠CDEEF=DC.在△AEF和△EDC中,∠AEF=∠EDC,AE=ED.所以△AEF≌△EDC(SAS).所以AF=EC,∠AFE=∠C=2∠B.因为LAFE=∠B+∠BAF,所以∠B=∠BAF.所以BF=AF,所以B=C所以BE=EF+BF=DC+EC

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    仅当M,A,F,三点共线时,等号成立,所以|MA+即△F,F2M是直角三角形,故MF,P+|MF22=|AF2+|MF2|=3a+|MA-|MF,≤4a=8,解得a=|F,F2P=400,又1|MF,-|MF21|=2a=16,所以之即。4由椭两方程可约名-所以||MF,-|MF21P=400-2|MF,I|MF2,解得|MF,|·|MF2|=72.3,故2c=2√a-b=2.5.(1,+)易知渐近线为1:22x-y=0,l2:-22x-8-2+=1由题知c=1,F,(-1,0),A(0,b),设y=0,所以直线n∥亿,故直线n与渐近线L,距离为54d=1,又点M在C的左支上,所以点M到渐近线l8(),由AB-PB1,可得-子F在,即的距离大于零,故点M到直线n的距离大于1.(-1,-b)=1w,得=子-子因36.A由题得a=4,b=3,双曲线的渐近线方程为y=3±,即3生4y=0由双曲线新近线关于:箱对称为点B在椭圆上,所以25,469a29b2=1,解得a2=5,所以可知点(3,0)到两条渐近线的距离相等,故d=6=51-4做横圆6:号兰-1|3×3-0×49V32+(-4)25基础点27双曲线6-1.B设渐近线方程为bx-ay=0,右焦点(c,0),右顶点(a.,0),由题得6c_26,故e=2怎么解题c1【腾远解题法:[2]3;[3]4:[4]2:[5]6-2.1,5易知渐近线方程为y=士。,因为sa【答案】47,所以ana=,又1与C没有交点,所以262W62I调远都题法,21,3到会,4号a≤1凳-智所以1号,则e21+s7[5]2a2;[6]3e;[7]2b【答案】27.B由双曲线方程可知渐近线方程为y=±x.设直3-1.线x=a与两条渐近线的交点的坐标分别为D(a,2516石1由感得台行即6=专①又的11②.由①②得。2=25,=16,故双曲线方程为11b),B(a,-b),所以Saae=2a[6-(-b)]=ab=8,而双曲线的焦距为2c,又c=√a2+b≥√2ab=4,当且dr=12516仅当a=b=2√2时取等号,所以2c≥8,故焦距的最小值为8.3-2.21易知该渐近线方程为y=名,4=号因为7-1.C设LE0D=a,则anQ=6,因为∠ED0e=25k,所以25a2=bc.因为焦点到ax-by=0的距离为2,所以d=|bc=6=2,即5c2-c-45=0,∠80F,直线y=-音(:-2)的斜率为-号,所以√a2+b所以c=50=1故=号分tan 2a=-品子释得ma总宁所以4-1.43+42易知a=b=2,c=2√2,|AF,-AF2=2a=4①,因为AF1⊥AF2,所以AF,1P+AF212=627-2.B由双曲线的定义知|PF|=0+2a=52①.又|F,F21=32②,由①②得|AF2+|AF,=43,所以a△AF,F2的周长为43+42.a,名0,e成等比数列,所以子=ac②.又+6=634-2.72由双曲线方程可得|F,F2=20,因为0M=c2③,联立①②③得c=22,所以a=√2,b=√6,故虚10=R,R,所以点M在以FR,为直径的圆上,轴长为26.腾远高考交流QQ群73050064257

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    1十)=i,故1=1,故选A误;当之1之2=之1之?时,有之1(x2一7.D由余弦定理的推论得2a·2之3)=0,又之1≠0,所以2=之3,故Ba2+b2-c=2b+c,所以a2+b2-8B因为:-1+2i=-1+2i正确;当2=之3时,则之2=之,所以2ab|之12212-x1之,12=(2122)(21之2)c2=2b2+bc,所以b2+c2-a2=一i一1+2i=一1+i,所以复数之在复一bc.由余弦定理的推论得cosA=面内对应的点(一1,1)位于第二象限,故(之1之3)(21之2)=之1之2之122-之1之3之1选B.之3=0,故C正确;当1之2=|之112时,6+c-a=-2月2bc9.C设之=a十bi(a,b∈R),因为之在复则之1之2=|之112=之121,可得212面内对应的,点位于第一象限,所以2121=之1(22之1)=0,因为之1≠0,所(0,),所以A=行若。=6,则由余a>0,b>0,由|之+乏|=2a|=1得以之1=之2,故D错误.故选BC弦定理得a2=b2+c2-2 bccos A=a2,因为复数之的模为1,所以17.-1反b2+c2+bc≥2bc+bc=3bc,当且仅当b=c时取等号,所以3bc≤36,解得(a+i)(1+i)十62=1,解得6=解析:2=1-D(1+D=a1a+6=√42c≤12.故S△Ae=2 esin A≤35.(负植合),所以:+所以=0,得10}i,因为:∈R,故a十122因此,△ABC的面积的最大值为3√3a=一1,所以之=一1,故之十i|=故选D.3:8.D令G(x)=mf(x)十ng(x)十x,因一故选C-1+i|=√2.:18.3-2i为y=f(x),y=x与y=g(x)都是10.A由题意知之为纯虚数,则可设之解析:由题设,得之1+乙2=1十i十2-奇函数,所以G(x)是奇函数,则G(x)bi(b∈R,b≠0),则之+乏=bi一bi=3i=3-2i.的图象关于原点对称.对任意x∈0;当之十乏=0时,可取之=乏=0,则之19.1-5i(0,十∞)都有F(x)≤F(2)=8,即为纯虚数不成立.故“之为纯虚数”是F(x)有最大值8,则G(x)有最大值6,11-3i解析:1十2i=1-3)1-20“之十乏=0”的充分不必要条件.故(1+2i)(1-2i)所以x∈(一∞,0)时G(x)有最小值选A.一6,而F(x)的图象是由G(x)的图象11.D设x=a十bi(a,b∈R),则乏=a1-6-25i=1-5i.5向上移2个单位长度得到的,所以F(x)在(一∞,0)上有最小值一6十bi,|之|=√/a2+b2,3z=|之+6i20.1+2i2=一4,故选D.→3a+6-.解析:因为(1一i)之=3+i,所以之=-+9+书(3+i)(1+i)9.ABD因为a=2e,b=一6e,所以2’即(-3b=6b=一3a,故D正确;由向量共线定理b=-2,知,A正确;一3<0,a与b方向相反,故B:=-21,则:在复面内对应的点3+3i+i+=1+2i2正确;|b|=3|a|,故C错误.故选ABD210.ABD由|a-b|=√3,可得(停-2)位于第四象限,故选D阶段滚动卷二1a-b12=|a12+Hb12-2ab=3,:1.DA={x|2≤x≤4},又B={1,2即1十b|2一2=3,解得1b|=2,所12.B =cos 0+isin cos3,4,5},故A∩B={2,3,4.故选D.以A正确;a·b=|a|·|b|cos0=1×62.C1-i(1-i0)21-2i+i1+i(1+i)(1-i)2Xcos0=1,所以cos0=2,又0∈1i22019[0°,180],所以0=60°,所以D正确,C不isinπ=一1,故选B.=(-i)20192正确;a·(b-a)=a·ba2=1-1=13.ABD设之=a+bi(a,b∈R),因为=i,虚部为1.故选C.0,则a⊥(b一a),故B正确.故选ABD之(之+2i)=8十6i,所以zz+2iz=8+sin B6i,所以a2b-2%》+2a二8+6,3.C“y=3cos((2x-)=11.AD cos B 6os2a=。-2nA-nc所以a2+b2一2b=8,2a=6,所以a=整理可得sin Bcos C=2 sin Acos B3,b=1,所以之=3+i,所以之的实部3cos[2(-)-],.将函数y=sin Ccos B,可得sin Bcos C+sinC·为3,虚部为1,故A,B正确;x乏=30s(2x-)的图象上的所有点向左cos B sin (B +C)=sin A|之12=10,故C不正确;之在复面上2sinA·cosB,,A为三角形内对应的点(3,1)位于第一象限,故D正确.故选ABD.移π个单位长度,可得到函数y=4角simA≠0,”c0sB=分故A正5i5i(1-2i)14.BC“x=1+2i=1+21-2D3cos(2x-于)的图象.故选C.确,B错溪:又B∈(0xB=号,2十i,则可知复数之的虚部为1,故A错4,D由存在量词命题的否定为全称量词误;之一2=i为纯虚数,故B正确;复数命题,则原命题的否定为Hx∈4,6=3,得3=由S=3V3,b4之的共轭复数为乏=2一i,其对应点为11(2,一1),在第四象限,故C正确;复数之(0,十∞),1+1≥0.故选D.acsinxaxcx2的模为|之|=√22+1=√5,故D错5.D因为12,c=1.1-11<1,所c2-ac=(a+c)2-3ac=(a+c)2-15.BC由复数相等可得仁b=3,。解,以b>a>c,故选D.9,解得a十c=3√2,故C错误,D正确.(a-1=-2,6.A易知f(x)的定义域为(0,十∞),且,故选AD.得a二-所以:=1+i)=1+f)=x-9又x>0,由f'(.x)=:12.AC.f(x)=x3-x+1,.f'(x)=b=一3,i)2=2i,对于A,之的虚部是2,故A错-9≤0,得00,的,点在虚轴上,故D错误.故选BC.16.BC取之2=1,之3=i,满足|22|=所以日十之8解得1<。≤2故|之3|,但是之2=士之3不成立,故A错:选A.fx)单调道增,当∈(-,红对闪·高考一轮复金卷数学204

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

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  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    第八章面解析几何3.(2022浙江宁波镇海中学高三模拟)已知点M(1,角度2弦长问题2)是圆C:x2+y2=r2内一点,直线1是以M为例2(1)(2022山东枣庄期末)过点A(2,2),作中点的弦所在的直线,直线m的方程为2x-y=2,那么倾斜角为的直线1,则直线1被圆0:+y2=A.l⊥m且m与圆C相切16-85截得的弦长为B.l∥m且m与圆C相切A1③2B.2-√3c.l⊥m且m与圆C相离D.l∥m且m与圆C相离C.3-√3D.6-234.(2020全国Ⅱ,5,5分)若过点(2,1)的圆与两(2)(2022河南郑州高三模拟)若直线1:3x+4y+坐标轴都相切,则圆心到直线2x-y-3=0的a=0(a∈R)与圆0:x2+y2=9交于不同的两点距离为()A、B,且10+0i1=51应1,则a=()D.42A.±55B.±3√5C.±25D.±55.若圆x2+y2=r2(r>0)上恒有4个点到直线l:x-方法感悟y-2=0的距离为1,则实数r的取值范围是1.求过某点的圆的切线问题时,首先应确定点与圆的位置关系,再求切线方程若点在圆上(即为切点),则过方法感悟该点的切线只有一条;若,点在圆外,则过该点的切线判断直线与圆的位置关系的常见方法有两条,此时注意斜率不存在时的切线。(1)几何法:利用d与r的关系判断。2.求圆的弦长问题的两种方法(2)代数法:联立方程之后利用△判断.(1)几何法:直线被圆藏得的半弦长}、弦心距d和2(3)点与圆的位置关系法:若直线恒过定点且定点在圆内,可判定直线与圆相交考点二圆的切线、弦长问题多元分析(2)代数法:利用弦长1AB1=√1+1x,-x21=√1+角度1圆的切线问题.1·√-4或1AB1=1+·yl例1已知点P(√2+1,2-√2),点M(3,1),圆C:(x-1)2+(y-2)2=4.·√(y+y2)2-4yy2(k≠0)求解(1)求过点P的圆C的切线方程;(2)求过点M的圆C的切线方程,并求出切迁移应用线长1.(2022河南安阳高三模拟)已知圆C:(x-2)2+(y-6)2=4,点M为直线l:x-y+8=0上一个动点,过点M作圆C的两条切线,切点分别为A,B,则四边形CAMB周长的最小值为()A.8B.62C.5√2D.2+4√22.(2020天津,12,5分)已知直线x-√3y+8=0和圆x2+y2=r2(r>0)相交于A,B两点.若1AB1=6,则r的值为3.(2021山东东营模拟)若圆C:x2+y2+6x-2y+n=0截直线l:(2+m)x+(2m-1)y-5m=0所得的最短弦长为4√2,则实数n=。181·

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    第十三章轴对称第2课时用坐标表示轴对称建议用时:30分钟(共271考:单独22考,在网格作图题、函数综合题等中涉及249考)教材改编题知识点2坐标与图形变化92考》基础《3.`(教材P71第2题改编)如图,△AB0与△DEF关于y轴对称,若点A的坐标为(1,-2),则对知识点1关于坐标轴对称的点的坐标9考称点D的坐标为()1.(教材P70第1题改编46考)一题多变A.(-1,2)B.(2,-1)1.1改变点坐标求关于x轴对称的坐标C.(-1,-2)D.(-2,-1)在面直角坐标系中,点A(-1,3)关于x轴2D的对称点坐标为A.(1,3)B.(3,-1)O(F)戈C.(-1,-3)D.(1,-3)A(1,-2)1.2改为关于y轴对称求字母的值第3题图第4题图在面直角坐标系中,点A(-4,a)与点B4.(教材P71第3题改编)已知长方形ABCD在(b,-2)关于y轴对称,则a,b的值为()坐标面上的位置如图所示,x轴,y轴分别是A.2,-4B.-2,4长方形的两条对称轴.若点A的坐标为(-3,C.-2,-4D.2,4-2),则点B的坐标为,点C的坐标1.3改为根据两点坐标判断两点关系为,点D的坐标为已知点Q(-2,-3)是由点P(-2,3)经过坐5.(教材P72第4题改编)如图,在面直角坐标的变化得到的,请直接写出它进行了怎样标系中,△ABC的顶点坐标分别为A(1,1),的运动:B(4,-1),C(2,3).2.(BS教材八上P72改编)在面直角坐标系(1)作出△ABC关于x轴对称的图形△A'B'C',中,已知点A(3,a+1)和点B(2b-1,2)并写出△A'B'C各顶点的坐标:(1)若点A到x轴和到y轴距离相等,求a(2)若将△ABC向下移4个单位,作出移的值;后的△A"B"C”,并写出△A"B"C"各顶点的坐标(2)若点A和点B关于y轴对称,求a+b的值..3-2-10第5题图49

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    2024届新高三秋季入学摸底考试数学注意事项:L,答卷前,考生务必将自己的姓名、准考证号等填写在答题卡和试卷指定位置上。2.回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。如需改动,用橡皮擦干净后,再选涂其他答案标号。回答非选择题时,将答案写在答题卡上。写在本试卷上无效。3.考试结束后,将本试卷和答题卡一并交回。一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1L71.已知集合P-xeNx(x-3≤0,Q=xx≥2,则PnQ=A.2B.{3C.{2,3D.10,2,3}2已知复数:,则z的虚部为A.iB.-1C.2D.13.函数f八x)=2+logx的零点所在区间是Ao引B(合C.(1,2)D.(2,3)n2,n≤5,4记5为数列a,的前n项和,若5=5n4,>5则a6=A.1B.5C.7D.95.已知向量a=(sinx,N3cosx),b=(1,-1),函数f八x)=a·b+1,则f(x)图象的一条对称轴的方程是Ax-6Bx-石Cx=号Dx=-号6.“太极图”因其形状如对称的阴阳两鱼互抱在一起,故也被称为“阴阳鱼太极图”,如图是放在面直角坐标系中的“太极图”,图中曲线为圆或半圆,已知点P(x,y)是阴影部分(包括边界)的动点,则,'的最小值为-2BC.-4D.-17,已知函数(x)=2xlnx的极小值为a,极小值点为b,零点为c.若底面半径为1的圆锥的高=a+2b+c,则该圆锥的体积为AB.mcD.T真我realmeShot on真我GT Neo5SE2023082722:16数学第1页(共4页)

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    49.A。根据If I give it up,what's left for me及to see himself as a vital part of the community可知,Freed觉得如果不能给病人看病,那他的生活中就什么都没有了,故推断,此处是说要让他继续把自已看成社区重要的一部分。50.D。51.C。根据he should write about his medical experiences if he was..to do it和a goodidea可知,“我”建议Freed如果可以的话,把他的医学经历写下来。52.B。根据pass on what've learned to the可知,Freed要把自己的所学传递给社区的人。本空与上文中的community构成原词复现:53.A。Freed医生80岁高龄还在努力,故可知,此处在说努力永远不嫌老。本空与下文中的older构成原词复现。54.B。根据上文Freed准备写书及during each phase of life可知,在生命的每个阶段都要做些调整55.A。根据my role now is to pass on what i''ve learned及a source of satisfaction可知,年老的时候,分享才智和经验往往让人感到满足。give of意为“贡献”,符合语境。第二节主题语境:人与自我一一做事本文是记叙文。Mazeda Begum通过种植有机蔬菜不仅改善了家里的经济状况,也激励着其他人投身农业56.settlement。.考查名词。设空处作hit的宾语,其前有Mazeda Begum's限定,应用名词。informal settlement意为“临时棚屋区”。57.barely。考查副词。设空处修饰enough,意为“勉强才能”,应用副词。本句中let alone意为“更不用说”。58.to close。考查动词不定式。force sb to do sth意为“迫使某人做某事”。59.who。考查关系代词。设空处引导非限制性定语从句说明Mazeda的具体情况,且在从句中作主语,故填who60.has created。考查现在完成时。since在句中是副词,意为“自从…以来”,与完成时连用,故填has created:61.affordable。考查形容词。设空处修饰produce(农产品),意为“买得起的”,应用形容词。62.t。考查it的用法。设空处在句中作形式主语,真正的主语是动词不定式to be a farmer。63.adding。考查动词-ing形式。分析句子结构可知,设空处应填非谓语动词;add的逻辑主语是she,与add之间是逻辑上的主谓关系,应用动词-ing形式64.earns。考查一般现在时。根据and之前分句的时态和之后的时间状语per month可知,该句介绍了Mazeda每个月的收入情况,此处应用一般现在时。65.the。考查冠词。in the near future意为“在不久的将来”。【词汇链接】1.make ends meet(para.1):勉强维持生计2.stand(para.1:货摊3.spring up(para.2:迅速出现;突然兴起4.follow suit(para.2小:仿效5.BDT(para.3):孟加拉国的货币单位符号

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    someone可知,毕加索玫瑰时期的形成主要是受爱情的影响。27.C。理解具体信息。根据倒数第二段中的Cubism was so unique and it became verypopular可知,立体主义时期的作品特色鲜明、与众不同。C篇主题语境:人与社会—社会本文是说明文。一般来说,家长都比较担心性格内向的孩子,认为他们以后的人生不会成功,然而,作家苏珊凯恩在她的书中提到:性格内向的人没必要努力让自己显得外向,内向的人也能成就伟大的事业。28.A。理解具体信息。根据第一段对Davis性格的描述及Davis told her she was crazy可知,Davis认为Jessica的提议很荒唐。29.D。理解具体信息。根据第二段中的But kids like Davis,who will be successful whenthey can be their naturally quiet selves,.should be valued too可知,Cain认为不应该只表扬性格外向的孩子,内向的孩子应该受到同等的重视。30.B。推断。第三段中提到比尔盖茨、奥巴马等名人是为了说明该段中的Many of thegreat contributors to this world in all kinds of fields have been introverts Theymade their contributions because of their quiet characters。由此可知,性格内向的人也可以闯出自己的一番天地,成就伟大的事业。31.B。推断。根据倒数第三段中的Davis quietly listened to what his classmates wanted和he knew what the school needed可知,相对于那个性格外向的班长竞选者提出的才艺表演赛、舞会等社交项目,Dvis的提议从学生的实际需要出发,更符合大家的需求。D篇主题语境:人与社会—社会服务

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    How's your new school life?Write and tell me.Yours,Li Hua第二节One possible version:Then,I noticed a man standing in front of a store.He looked at the dogs,looked at me,and thentook off after the dogs.He ran to them and stopped them just as they were about to cross a busyroad.I slowed down to catch my breath as I saw he had the dogs under control.Then a thoughtsprang to mind:How was I going to get the table back to the restaurant while controlling twolarge dogs?By the time I walked up to the man and the dogs,he had untied them and had the table up onone of his shoulders.I thanked him while he passed Zoe and Tyler's leashes to me and walked offto the restaurant.By the time Tyler,Zoe,and I got back to the coffee shop,the man had just puteverything in the outside dining area in place.It looked as if nothing had ever happened.Iwanted to show him my thanks with more than just words.So,I bought a cup of tea for him.Theman thanked me for the tea,saying it was the best he had ever had.写作选做题1.She helps in a local school as a volunteer every Wednesday.2.There was a big change in our lifestyle after we moved to the city.3.She spends two hours on the phone chatting to her friends every Sunday.4.We should play the game according to rules.5.I can't go to a movie tonight.I have to revise for my English exam tomorrow.部分解析阅读第一节A篇主题语境:人与社会一一社会服务本文是应用文。文章介绍了一个图书展览会。2l.D。理解具体信息。根据第三段中的But it's not only books that people are searching for;the Book Fair is also a great place to find records,,CDs,and DVDs可知,该图书展览会不仅展销图书,还有唱片、光盘和数码光碟。22.C。理解具体信息。根据第四段中的The Book Fair opens at4p.m.on Thursday,May4.Onthat day only,,aSl5 admission is required可知,该图书展览会于星期四下午四点开始,只有这天的门票是15美元。23.D。推断。根据第四段中的all remaining books are half--price from10a.m.to6p.m.onSunday可知,星期天,该图书展览会从上午十点开始到下午六点结束,所有图书半价销售。B篇主题语境:人与自我一一生活与学本文是记叙文。作者讲述了自己抉择大学专业的过程和感受。24.D。理解具体信息。根据第二段中的I came into college thinking that I would major inCommunications.It had been my dream to be a sportswriter That was my dream until I got theacceptance letter that stated I was not qualified for that major可知,作者的梦想是成为一名体育记者,所以,上大学时她以为自己会学传播学专业。然而,录取通知书上说她不符合传播学专业所要求的条件,所以她只好放弃当一名体育记者的梦想。25.C。推断。根据第三段的内容及第四段“What are you going to do with a degree in History?

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    1四、解答题:本题共6小题,共70分解答应写C.当0217.(10分)e的品用20m长的铁丝折成一个矩形,若使其面积最大,应当怎样折?D.当a>时,不等式的解集为xx<年12或x>011.已知a>0,b>0,且3a+2b=1,下列说法正确的是A)A.ab的最大值为24哈品对脉()N·明是静0出B。+的最小值为3x1大量嘴床0(mn).xC.。2+8的最小值为3又匹hr中()i(r网D.9a2+462的最小值为112.已知关于x的不等式aax2+bx+c≥0的解集为{x1x≤-3或x≥4},则下列说法正确的是个)A.a>0B.不等式bx+c>0的解集为{x1x<-4}18.(12分)C.不等式cx2-bx+a<0的解集已知x,y都是正数,证明:为xlx<-41或x>3(0+=2D.a+b+c>O(2)(x+)(x2+y2)(x3+y)≥8xy2.三、填空题:本题共4小题,每小题5分,共20分13.若20,8>0,写84,则a+厅的最大值为16已匆不号式8管女88的部界是关于x的不等式2x2+ax-9<0的解集的一个子集,则实数a的取值范围为

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    第4版详情请参考答案解析阅读理解1-4 CBDD完形填空1-5 DBACC6-10 ABDCB 11-15ADBAD阅读填空1-5 DFEAG2。

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    项和为S,则S2023C.)2023.2025法国数学家傅里叶用三角函数诠释美妙音乐,代表任何周期性声音和动的函数表达式都是A.1012B.2020形如y=Asinox的简单正弦型函数之和,这些正弦型函数各项的频率是最低频率的正整数倍(频率是指单位时间内完成周期性变化的次数,是描述周期运动频繁程度的量).其中频率最低的一8项所代表的声音称为第一泛音,第二泛音的频率是第一泛音的2倍,第三泛音的频率是第一泛音的3倍…、例如,某小提琴演奏时发出声音对应的震动模型可以用如下函数表达:y=0.06sin10001+0.02sin2000t+0.01sin3000/(其中自变量1表示时间),每一项从左至右依次称为第一泛音、第二泛音、第三泛音.若一个复合音的数学模型是函数∫()=inx+)inox(xeR)(从左至右依次为第-一泛音、第二泛音),给出下列结论:①(x)的一个周期为3元:②f(x)的图象关于直线=2n对称:③()的极小值为-39,国()在区间[0,2网上有2个零点,其中正确结论的个数有D.4个A1个B.2个C.3个多项选择题:本大题共4小题,每小题5分,共20分.在每小题给出的选项中,有多项符合题目要求。全部选对的得5分,部分选对的得2分,有选错的得0分.二、已知a>0,b>0,且a+b=2,则2°+202491og2a+log2b≤0a2+b2≥42a+=a-2ani(n∈N+),则下列结论正确的是10.i知数列{a,}满足4=2201侵斗为等比数列an0B,{a,}为递增数列的前n项和T.=2*2-2n-4{a,}的通项公式为a,=2-211.己知正方体ABCD-4C,D的棱长为1,若点P在线段AD,上运动(不含端点),则下列结论正确的是A.直线B,PI面BDCV1A0,△BPD周长的最小值为2+√2c.三棱维B-PD与三棱锥C-PCD的体积之和为后√当2AP=PD,时,DP与面BC,D,所成角的正切值为312.已知f(x)=2,则下列有aln(x+1),x≥0A.对于任意a∈R,函数f(x)有且只有两个零点V太1以当a<0时,函数f(x)有三个极值点C.当x∈(-0,0)时,函数∫()的图象的切线的斜率最小值为-】B.toC(12,o)黄数L上-上的0小值为则[)P0,14sho若款6 nePlus江西省,岸乡市202方692:)P:色P(-,y741X

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    2l.C。理解具体信息。根据What's Included部分An English-speaking driver guide可知,柏林周边四天旅行有导游陪同。22.D。理解具体信息。根据Day2:Berlin-Meissen部分.touring the oldest PorcelainManufactory in Europe,as well as the museum and production room inside.可知,Meissen的g独特之处在于其瓷器制作历史悠久。23.A。推断。根据Day4:Dresden-Weimar-Berlin部分the commemorative imagesGermany's most famous poets..可推知,诗歌爱好者可能最喜欢参观Weimar。B导语:本文是一篇记叙文,属于“人与自我”主题语境。文章讲述了作者·一夜间失明,经历了震惊、消沉,最终走出困境、重拾生活信心的故事。24.D。推断。根据第一段I was always looking for a real adventure,something new and excitingI enjoyed a joyful life.可推知,作者在33岁生日之前过着充满冒险的幸福生活。25.A。理解态度。根据第三段I couldn't process what I'd heard at first;:it just didn’t seem tomake sense.可推知,作者非常震惊,无法接受自己失明的事实。26.C。理解具体信息,根据第五段The turning point came...it made such a difference to be ableto talk to people who understood my situation.可知,与其他视力受损的人交谈之后,作者改变了之前对生活自暴自弃的态度,转而接受并适应失明后的生活。27.B。理解主旨要义。本文主要讲了作者一夜间失明,经历了震惊、消沉,最终走出困境、重拾生活信心的故事,故选用此标题。导语:本文是一篇说明文,属于“人与自然”主题语境。精准农业专家Strahl介绍了公司研发的新技术,该技术能够更精准地观测农业产量,以帮助农民调整种植策略。28.B。理解具体信息。根据第一段.there are so many new products...take time to test on thefarm to see if they can bring value可知,精密农业的新产品需要时间试验是否有效,这可能是一些农民不愿意应用新产品的原因。29.C。理解词汇。根据第二段he enjoys...testing the technologies.to see what is worth...usingthe data.study seeding methods.可推知,Strahl喜欢待在农田里,测试各种技术和产品是否“可行”。30.D。理解具体信息。根据第四段Optimus…provide growers with tools.It also allowsfarmers to see an in-depth study of variable--rate products..可知,Optimus为农民提供田间精准的数据和工具。3l.D。推断。根据末段Applying the variable rate will take a full growing season to get the resultsback,but it can help you make better management decisions for years to come.可推知,新产品虽然需要整个生长季节才得到结果,但能帮助农民在未来制定更好的种植策略,所以其长期的潜在益处很大。D导语:本文是一篇说明文,属于“人与自然”主题语境。利用椰子壳纤维制作的材料可以防止海水侵蚀海岸。32.C。理解具体信息。根据第二段The coconut material is easy to get and costs a lot less thanbarriers made of other materials可知,椰子壳纤维材料因其易得性和价格低廉而在建造海岸线屏障上得到广泛使用。33.C。理解具体信息。根据第四段.pre-seeded with shoreline plants and grasses.in the coirmaterial可知,提前种植海岸植物可以应对椰子壳纤维材料的老化问题。34.A。推断。根据末段It's not for every site;it has to be site-specific.it doesn't work in all

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

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  • 2024年衡水金卷分科综合卷老高考英语三全国二卷英语x

    【语篇导读】本篇为游记散文。文章讲述了作者体验西班牙城市Caz的感受,着重讲述了Ca击z的地理位置、自然风光、食品文化以及“歌唱城市”这个名字的由来。28.B词句猜测题。根据第一段However,no city will ever quite match Caliz.where1 spent sixmonths studying as a student..(然而,设有哪个城市能与Caliz媲美,我曾在那里学了6个月。)可知,刻线词指代在Caiz学。29.A主旨大意题。通读第三段的内容可知,该段主要介绍了Cdiz的地理位置和景色。30.C细节理解题。根据第五段During those ten days,Cadiz's narrow streets are filed with thesound of singing as musical groups fight for a place in the contest,which takes place on thelastSaturday of camnival.(在这十天的时间里,Cadiz狭窄的街道上回荡着歌声,各音乐团体为在狂欢节的最后一个周六的比赛中获得一席之地而相互竞争。)可知,Ciz被称为“歌唱之城”是因为在一年一度的狂欢节上,到处都是歌声。31.B推理判断题。根据最后一段I am currently living in Iluelva,just a short drive from Cadiz.so please pay attention to my next sharing!(我现在住在Huelva.离Cadiz只有很短的车程,所以请关注我的下一个分享)可推断,本文最有可能出自网上的一则帖子。D【语篇导读】本篇是说明文。介绍了一个名为RemoveDEBRIS的实验清理设备成功地在颗虚拟卫星周围撒网,模仿一种有朝一日可能收集太空垃圾的技术。同时介绍了RemoveDEBRIS卫星的工作原理以及面临的问题。32.B细节理解题。根据第二段中的it symbolizes an early step.junk in space.由此可知:RemoveDEBRIS卫星的用途是收集并处理太空垃圾。33.C细节理解题。第五段Guglielmo aglietti所说的话可知,RemoveDEBRIS卫星是通过撒网将碎片拖出轨道来运作的。34.D词义猜测。根据第六段内容There are still enormous bariers to clear before operationalcleanup tasks are underway,he noted,and the most discouraging is figuring out how to fund suchprojects.(他指出,开展作业清理任务之前,仍有巨大的障碍需要清除,最令人沮丧的是弄清楚如何为这些项目提供资金。)可知,困难是说服相关部门资助这些任务,为这些项目提供资金支持一资助。故可推测划线单词的意思为“支持、帮助”第4页共10页

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    阅读:21~23 DACA篇:本文是应用文。文章介绍了四种对人的记忆力有益的食物。21.D【解析】细节理解题。根据第二段第二句可知,作者建议我们每天至少要吃两份蔬菜。22.A【解析】细节理解题。根据四种食物的介绍可知,它们都对人的记忆力有益。23.C【解析】推理判断题。文章介绍了四种对人的记忆力有益的食物,所以本文最有可能选自一本健康杂志。2427DBBAB篇:本文是记叙文。在明尼苏达州,一只黑熊在涵洞中被困三天后获救。24.D【解析】细节理解题。根据第二段第二句可知,这只黑熊被困在涵洞中。25.B【解析】细节理解题。根据第三段最后一句可知,这只黑熊还处于冬眠状态。26.B【解析】主旨大意题。根据第五段的内容可知,本段主要描述了人们为救这只黑熊所做的事。27.A【解析】推理判断题。根据最后一段中Andrew说的话可知,就如何帮助受困的熊,他给出了自己的建议。28~31 ADABC篇:本文是说明文。考古学家发现了隐藏在尤卡坦半岛丛林深处的玛雅遗址。28.A【解析】细节理解题。根据第二段最后一句可知,这个遗址的核心区域遍布着用石头建造的建筑物。29.D【解析】推理判断题。根据第四段可知,Sprajc认为这个遗址是宝贵且有重要意义的。30.A【解析】推理判断题。根据第五段的内容可推知,这个遗址曾是一座繁荣的城市。31.B【解析】主旨大意题。通读全文可知,考古学家发现了隐藏在尤卡坦半岛丛林深处的玛雅遗址。32~35 CCBDD篇:本文是说明文。文章介绍了个体心理学。32.C【解析】推理判断题。通读全文可知,作者在第一段提及The Courage to be Disliked是为了引出文章的主题。33.C【解析】细节理解题。根据第二段最后两句可知,关于恐惧和悲伤,Adler认为它们是可以被个人选择克服的。34.B【解析】词义推测题。根据画线词所在句和上文可知,Adlr认为,一个人不愿意走出家门,因为这个人每次走出去都充满焦虑和恐惧。所以Adler断言,这个人制造了恐惧和焦虑,以便他待在家里。assert意为“断言”,与claim同义。35.D【解析】推理判断题。通读全文可知,通过介绍个体心理学,作者希望人们能够摆脱曾经的创伤,着眼现在和未来。36~40 CGBFD七选五:本文是说明文。文章介绍了关于黑匣子的一些知识。【高三英语·参考答案第5页(共10页)】·24-124C·

  • 2024年衡水金卷分科综合卷老高考英语三全国二卷英语x

    The Female Brain through the LifespanInstructor;Louann BrizendineDATE:September 30 (1 Saturday)Join bestselling author Dr.Louann Brizendine for aTIME:10:30AM-1:30PMdeep dive into the female bruin.Discover the inner-working,LOCATION:Corte Madera Storepossibilities,and opportunities that women are offered overtheir lifetimes.Race and the Constitution(宪法)Instructor:Joel Richard PaulDATES:October 1-22 (4 Sundays)Join Joel Paul,a law professor and author,for a livelyTIME:IPM-3PMwide-ranging discussion of the legal struggle for racial justiceLOCATION:Corte Madera Storein our count灯y.Impressionism:The International MovementInstructor:Kerrin MeisWe are familiar with Impressionism in France and howartists took up painting to record the fleeting moment.In thisDATES:November 3 17 (2 Fridays)class,Kerrin Meis will show us how artists in otherTIME:1PM-3:15PMLOCATION:Corte Madera Storecountries outside of France -shared the same idea withwonderful results,reflecting the particular light,landscapeand traditions of their country.21.Who might be most interested in Nina Schulyer's class?A.Those who are fond of technology.B.Those who major in preschool education.C.Those who are crazy about travelling.D.Those who serve as medical workers.22.Which class can offer a feast for eyes?A.AI for Amateurs.B.Race and the Constitution.C.The Female Brain through the Lifespan.D.Impressionism:The International Moyement.23.What do these classes have in common?A.They all last for two hours.B.They are about arts and culture.C.They are given in the same place.D.They take place on weekends.BNo matter how beautiful the weather may be,the ocean can turn deadly in the blink of an eye.South African local Tongai Matandirotya has worked as a bartender at the Brass Bell Kalk Bayrestaurant for the past 8 years.Coworkers describe him as a "wonderful,loveable,fun human being."After watching him jump into action to save lives after an unexpectd accident on the shore,they'readding another description to his character:Heroic.Tongai was tending the bar one aftemnoon on a beautiful day with crystal-clear blue skies andcalm seas.Tourists who had finished their lunch at the restaurant were walking along the water's edge,taking in the stunning ocean and mountain views,when suddenly a "wall of water"rose up andcarried dozens of people out to sea."I saw this wave come over the harbour and it covered the people,dragging them into theocean,"Tongai recalled."It was frightening but I immediately ran outside,undressed myself,anddived into the water because I saw a child go in as well.I have a very soft spot for kids,and myinstinct (just kicked in to see if I could help."There was a powerful riptide at play,making it difficult for the shocked victims to get back tohore.Clair Gardiner and her 8-year-old daughter,Arya van Hilten,were knocked into the water.英语试题第3页(共8页)

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    39 Then,start attaching images to information you want to remember:shopping lists,addresses,brilliant ideas.By doing so,you'll find that you soon become more observant,bet- ter with details,and more confident about recalling the things that matter. 40,and use pictures to help you to set some new "per- sonal bests"for your own memory power! A.So learn from the champions B.Picture them,as vividly as you can C.And by letting your brain engage with them in new ways D.There are two kinds of memory:short-term and long term E.After a few minutes,cover the page and see how many

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    【答案】3640 DBFEC

  • 2024届衡水金卷先享题 分科综合卷 全国乙卷 英语(一)1试题

    Still,Janet was growing more nervous y with each step closer to the old man's house.When they got close enough,Dawson looked up with his usual frown(皱眉),but when he saw it was Amy,a broad smile changed his entire face as he said,"Hello, Miss Amy.I see you've got a little friend with you today. Amy smiled back and told him Janet was staying overnight and they were going to listen to music and play games.Mr Daw- son said that sounded fun,and offered them each a fresh picked apple off his tree.They gladly accepted.Mr Dawson had the best apples in the whole town. When they left,Janet asked Amy,"Everyone says he's the meanest man in town.How come he was so nice to us?" Amy explained that when she first started walking past his

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    25.Which can best describe Fahey's ride experience in Africa? A.Incredible.B.Lonely. C.Free. D.Cosy. 26.Why did Fahey launch Apidura? A.To help cyclists carry traveling stuff. B.To make her investment profitable. C.To call for bicycle traveling. D.To guide people across Africa. 27.【典型情境题】What is the text mainly about? A.A tough path to fame. B.An adventure across Africa. C.The benefits of green traveling. D.The story behind Apidura.

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

  • 衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A

    猢南省2024届高三九校联盟第一次联考数学参考答案命题学校:湖南师大附中审题学校:武冈市一中一、选择题(本大题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的)题号12345678答案DCABDCD1.D【解析】A∩B=A=ACB,而B=1,2,若a=0时A=必,满足条件:若a≠0时,A=(-},要使ACB,艮雪1,或=2所以Q1或Q-所以满足条件的实教口有3个,故选D版权所有m2+m-2=0,2.C【解析】由复数之=m2+m一2一(m一1)i是纯虚数,得解得m=-2.故选C.翻P火必究m一1≠0,3.A【解析】因为cos20后00=(cas9-m)-9,中osg-n0=子,两边方可得sinl(什)号(sn0叶cos0)cos0-2inos0叶sin0-1-sn20-16解符sin20-18故选A4.B【解析】设第n年的维修保养费为am万元,数列{an}的前n项和为Sn,该机的年均耗费为p,据题意,数列{a}是首项为12,公差为4的等差数列.则pS+98-[12m+nnD×4+98]=2+98+10≥2,√2·8+n210=38当且仅当2明即=7时p取最小位38,所以这台冰漫凌机的使用年限是7年,故选B5.B【解析】在y=g(x)的图象上任取一点(x,g(x),它关于x=1的对称点为(2一x,g(x).故点(2-x,g(x)在y=f)的图象上,从而g(x)=f(2-z)=3sin[(2-x)-ξ]=3sin(受-至x-号)=3co(至x十晋)当0≤号时,晋<牙x十音<,由y=c0s1在[吾,]上单调递减可知y=8x)在区同[0,号]上的最大值为g()=原c0s吾-号,故选R6.D【解析】由题意知正八面体的棱为原正四面体每个侧面三角形的中位线,故正八面体由棱长为2的两个正四棱锥构成,正四棱锥的底面是边长为2的正方形,取正方形一组对边中点,作出轴截面,利用相似或者等面积可算出内切球半径r写,故内切琼体积为V-青w-)》'-8,放选D7.C【解析】A店=AC+C成=AC+号(Ci+C)=AC+号(号C店+号C+号Ci=n+号(-m)+号·(-)-号·(一m》〉-8m+8n,故选C8.D【解析】设AB=x,内切圆圆心为I,内切圆在BF2,AF2上的切,点分别为U,V,由BF=a及双曲线的定义可知,BF,=3a,AF,l=x-Q,F,U=F,V=(BF+|AF,-AB)=a=r,故四边形IUF,V是正方形,得AF2⊥BF2,于是|BF2|2+AF2|2=|AB|2,故x2=9a2十(x-a)2,所以x=5a,于是cos∠FBF2=-是,在△FBF中,由余孩定理可得E=BF+BF,-2BEBE·cos∠FBE-c,从而-a,所以e=台-故选D数学试题参考答案一1

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    In the new study,Burda's graduate student,Kater ina Benediktova,initially put video cameras and GPS trackers on four dogs and took them on trips into the forest.The dogs would run after the flavor of an animal for 400 meters on average.The GPS tracks showed two types of behavior during their return trips to their owner.In one,named tracking,a dog would turn its original route back,probably following the same flavor.In the other behavior,called searching,the dog would return along a completely new route,making a way through the jungle with out any backtracking.

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    第四部分写作(共两节,满分35分) 第一节短文改错(共10小题;每小题1分,满分10分) 假定英语课上老师要求同桌之间交换修改作文,请你修改你 同桌写的以下作文。文中共有10处语言错误,每句中最多有两处。 每处错误仅涉及一个单词的增加、删除或修改。 增加:在缺词处加一个漏字符号(∧),并在其下面写出该加的 词。 删除:把多余的词用斜线(八)划掉。 修改:在错的词下划一横线,并在该词下面写出修改后的词。 注意:1.每处错误及其修改均仅限一词; 2.只允许修改10处,多者(从第11处起)不计分。 One day when I was in a restaurant had a quiet lunch,two

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    第四部分写作(共两节,满分40分) 第一节(满分15分) 假定你是李华,你校学生会打算组织题为“中西教育体系之异 同”的活动。请你给外教Mr Edward写封邮件邀请他参加,并请他 对活动内容提一些建议。要点如下: 1.活动时间、地点; 2.内容介绍。 注意:写作词数应为80左右。

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    up and say something.And we can do it with grace,by handling it without a bit of aggression and without being rude ourselves. Because once rude people can see their actions through the eyes of others,they are far more likely to end the rudeness them- selves. 24.What happened when Robert Winston was on the train to Manchester? A.A woman approached and shouted at him. B.Some journalists squeezed into the crowded train. C.A woman doctor sent rude messages on the Tweet. D.A woman talked on the phone loudly in others'presence.

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    W:I was so busy.First I was late to meet my sister at the air- port,and then we went to the hotel and it was full! M:I hope everything's OK! (Text 6) W:Good evening,sir.I'm the Assistant Manager.We've had a complaint from your neighbor about the noise.He is trying to sleep as he has an early start tomorrow for an important meeting.I'm sure you understand. M:Oh,I see. W:Do you think it might be possible to ask your friends to be a little quieter? M:Oh.I'm sorry.I suppose we were talking rather loudly.It's just that we've reached an important agreement.We were

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    1、衡水金卷先享题2024答案数学分科综合卷 新教材乙卷A


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